What is the integral of-4x^7sin(x^8) ?

The integral of-4x^7sin(x^8) is 1/2 cos(x^8)+C

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integral of-4x^7sin(x^8)

\int - 4 x^{7} sin (x^{8}) d x

\frac{1}{2} cos (x^{8}) + C

Solution steps

\int - 4 x^{7} sin (x^{8}) d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - 4 \cdot \int x^{7} sin (x^{8}) d x

Apply u-substitution

: \int \frac{sin ( u )}{8} d u

= - 4 \cdot \int \frac{sin ( u )}{8} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - 4 \cdot \frac{1}{8} \cdot \int sin (u) d u

Use the common integral:

\int sin (u) d u = - cos (u)

= - 4 \cdot \frac{1}{8} (- cos (u))

Substitute back

u = x^{8}

= - 4 \cdot \frac{1}{8} (- cos (x^{8}))

Simplify

- 4 \cdot \frac{1}{8} (- cos (x^{8})) : \frac{1}{2} cos (x^{8})

= \frac{1}{2} cos (x^{8})

Add a constant to the solution

= \frac{1}{2} cos (x^{8}) + C

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What is the integral of-4x^7sin(x^8) ?
The integral of-4x^7sin(x^8) is 1/2 cos(x^8)+C