What is the integral of (x-1)x^{1/2} ?

The integral of (x-1)x^{1/2} is 2/5 x^{5/2}-2/3 x^{3/2}+C

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integral of (x-1)x^{1/2}

\int (x - 1) x^{\frac{1}{2}} d x

\frac{2}{5} x^{\frac{5}{2}} - \frac{2}{3} x^{\frac{3}{2}} + C

Solution steps

\int (x - 1) x^{\frac{1}{2}} d x

Expand

(x - 1) x^{\frac{1}{2}} : x^{\frac{3}{2}} - x^{\frac{1}{2}}

= \int x^{\frac{3}{2}} - x^{\frac{1}{2}} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int x^{\frac{3}{2}} d x - \int x^{\frac{1}{2}} d x

\int x^{\frac{3}{2}} d x = \frac{2}{5} x^{\frac{5}{2}}

\int x^{\frac{1}{2}} d x = \frac{2}{3} x^{\frac{3}{2}}

= \frac{2}{5} x^{\frac{5}{2}} - \frac{2}{3} x^{\frac{3}{2}}

Add a constant to the solution

= \frac{2}{5} x^{\frac{5}{2}} - \frac{2}{3} x^{\frac{3}{2}} + C

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What is the integral of (x-1)x^{1/2} ?
The integral of (x-1)x^{1/2} is 2/5 x^{5/2}-2/3 x^{3/2}+C