What is the derivative of 4x+(64/x) ?

The derivative of 4x+(64/x) is 4-(64)/(x^2)

What is the first derivative of 4x+(64/x) ?

The first derivative of 4x+(64/x) is 4-(64)/(x^2)

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\frac{d}{d x} (4 x + \frac{64}{x})

4 - \frac{64}{x ^{2}}

Solution steps

\frac{d}{d x} (4 x + \frac{64}{x})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (4 x) + \frac{d}{d x} (\frac{64}{x})

\frac{d}{d x} (4 x) = 4

\frac{d}{d x} (\frac{64}{x}) = - \frac{64}{x ^{2}}

= 4 - \frac{64}{x ^{2}}

f (x) = 3 x - 9

x \to 3 lim (\frac{x ^{2} - 2 x + 1}{2})

(3 \frac{y}{x} - 8) d x + 3 d y = 0

y = \frac{1}{sin ^{2} ( x )}

\frac{d y}{d x} = 7 x cos (x^{2})

What is the derivative of 4x+(64/x) ?
The derivative of 4x+(64/x) is 4-(64)/(x^2)
What is the first derivative of 4x+(64/x) ?
The first derivative of 4x+(64/x) is 4-(64)/(x^2)