What is the integral of-0.00006x^2+6 ?

The integral of-0.00006x^2+6 is -0.00002x^3+6x+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of-0.00006x^2+6

\int - 0.00006 x^{2} + 6 d x

- 0.00002 x^{3} + 6 x + C

Solution steps

\int - 0.00006 x^{2} + 6 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= - \int 0.00006 x^{2} d x + \int 6 d x

\int 0.00006 x^{2} d x = 0.00002 x^{3}

\int 6 d x = 6 x

= - 0.00002 x^{3} + 6 x

Add a constant to the solution

= - 0.00002 x^{3} + 6 x + C

\int \frac{sec ^{2} ( x )}{2 + tan ( x )} d x

\int \frac{5 x}{e ^{x}} d x

\int ln (3 x^{3}) d x

\int (- x)^{2} d x

What is the integral of-0.00006x^2+6 ?
The integral of-0.00006x^2+6 is -0.00002x^3+6x+C