What is the integral of (x^2-6x+10) ?

The integral of (x^2-6x+10) is (x^3)/3-3x^2+10x+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of (x^2-6x+10)

\int (x^{2} - 6 x + 10) d x

\frac{x ^{3}}{3} - 3 x^{2} + 10 x + C

Solution steps

\int x^{2} - 6 x + 10 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int x^{2} d x - \int 6 x d x + \int 10 d x

\int x^{2} d x = \frac{x ^{3}}{3}

\int 6 x d x = 3 x^{2}

\int 10 d x = 10 x

= \frac{x ^{3}}{3} - 3 x^{2} + 10 x

Add a constant to the solution

= \frac{x ^{3}}{3} - 3 x^{2} + 10 x + C

\int sin^{2} (10 t) sec^{4} (10 t) d t

\int \frac{1}{x + 1} - \frac{1}{x + 2} d x

\int \frac{x ^{2}}{( x ^{2} - 1 ) ^{5}} d x

\int (1 - x^{2})^{\frac{3}{2}} x^{3} d x

\int \frac{3 x - 1}{( x + 2 ) ^{2}} d x

What is the integral of (x^2-6x+10) ?
The integral of (x^2-6x+10) is (x^3)/3-3x^2+10x+C