What is the integral of (sech^2(ln(x)))/x ?

The integral of (sech^2(ln(x)))/x is tanh(ln(x))+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of (sech^2(ln(x)))/x

\int \frac{sech ^{2} ( ln ( x ) )}{x} d x

tanh (ln (x)) + C

Solution steps

\int \frac{sech ^{2} ( ln ( x ) )}{x} d x

Apply u-substitution

: \int sech^{2} (u) d u

= \int sech^{2} (u) d u

Use the common integral:

\int sech^{2} (u) d u = tanh (u)

= tanh (u)

Substitute back

u = ln (x)

= tanh (ln (x))

Add a constant to the solution

= tanh (ln (x)) + C

\int 8 x^{4} + 4 x^{3} - 6 x^{2} - 4 x + 5 d x

\int + 50 x d x

\int \frac{7}{x ^{2} 9 a ^{2} - x ^{2}} d x

\int \frac{2 x - 3 x ^{2} + 4 x ^{3}}{x ^{4}} d x

\int (x^{2} + 1) e^{x^{3} + 3 x + 1} d x

What is the integral of (sech^2(ln(x)))/x ?
The integral of (sech^2(ln(x)))/x is tanh(ln(x))+C