What is the integral of e^{(32x)/3} ?

The integral of e^{(32x)/3} is 3/32 e^{(32x)/3}+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of e^{(32x)/3}

\int e^{\frac{32 x}{3}} d x

\frac{3}{32} e^{\frac{32 x}{3}} + C

Solution steps

\int e^{\frac{32 x}{3}} d x

Apply u-substitution

: \int e^{u} \frac{3}{32} d u

= \int e^{u} \frac{3}{32} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{3}{32} \cdot \int e^{u} d u

Use the common integral:

\int e^{u} d u = e^{u}

= \frac{3}{32} e^{u}

Substitute back

u = \frac{32 x}{3}

= \frac{3}{32} e^{\frac{32 x}{3}}

Add a constant to the solution

= \frac{3}{32} e^{\frac{32 x}{3}} + C

\int e^{- s t + 2 t} d t

\int (cos (x) + \frac{1}{x} - 1) d x

\int \frac{x}{x ^{4} - 12 x ^{2} + 35} d x

\int \frac{x ^{2}}{( 1 + x ^{3} ) ^{1.9}} d x

\int 3 (x + 1) 2 d x

What is the integral of e^{(32x)/3} ?
The integral of e^{(32x)/3} is 3/32 e^{(32x)/3}+C