What is the integral of (x^2-1)/(\sqrt[3]{x)} ?

The integral of (x^2-1)/(\sqrt[3]{x)} is 3/8 x^{8/3}-3/2 x^{2/3}+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of (x^2-1)/(\sqrt[3]{x)}

\frac{3}{8} x^{\frac{8}{3}} - \frac{3}{2} x^{\frac{2}{3}} + C

Solution steps

Expand

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

\int x^{\frac{5}{3}} d x = \frac{3}{8} x^{\frac{8}{3}}

= \frac{3}{8} x^{\frac{8}{3}} - \frac{3}{2} x^{\frac{2}{3}}

Add a constant to the solution

= \frac{3}{8} x^{\frac{8}{3}} - \frac{3}{2} x^{\frac{2}{3}} + C

\int sin (θ) tan (θ) d θ

\int \frac{4 x + 1}{x ^{2} - 5 x + 6} d x

\int \frac{x - 4}{x ^{2} + 3 x + 2} d x

\int \frac{x - x ^{3}}{x} d x

\int 2 - e^{- x} d x

What is the integral of (x^2-1)/(\sqrt[3]{x)} ?
The integral of (x^2-1)/(\sqrt[3]{x)} is 3/8 x^{8/3}-3/2 x^{2/3}+C