What is the integral of 10e^{t/(100)} ?

The integral of 10e^{t/(100)} is 1000e^{t/(100)}+C

Popular >

integral of 10e^{t/(100)}

\int 10 e^{\frac{t}{100}} d t

1000 e^{\frac{t}{100}} + C

Solution steps

\int 10 e^{\frac{t}{100}} d t

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 10 \cdot \int e^{\frac{t}{100}} d t

Apply u-substitution

: \int e^{u} \cdot 100 d u

= 10 \cdot \int e^{u} \cdot 100 d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 10 \cdot 100 \cdot \int e^{u} d u

Use the common integral:

\int e^{u} d u = e^{u}

= 10 \cdot 100 e^{u}

Substitute back

u = \frac{t}{100}

= 10 \cdot 100 e^{\frac{t}{100}}

Simplify

= 1000 e^{\frac{t}{100}}

Add a constant to the solution

= 1000 e^{\frac{t}{100}} + C

\int \frac{2 x - 1}{( x - 3 ) ^{2}} d x

\int \frac{- 7 x + 1}{( x + 1 ) ( x - 1 ) ^{2}} d x

\int \frac{9 cosh ( x )}{x} d x

\int 3^{x} sec^{2} (3^{x}) d x

\int \frac{1}{P ( 1 - \frac{P}{K} )} d P

What is the integral of 10e^{t/(100)} ?
The integral of 10e^{t/(100)} is 1000e^{t/(100)}+C