What is the integral of 4-7x^2+\sqrt[5]{x} ?

The integral of 4-7x^2+\sqrt[5]{x} is 4x-(7x^3)/3+5/6 x^{6/5}+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of 4-7x^2+\sqrt[5]{x}

\int 4 - 7 x^{2} + 5 x d x

4 x - \frac{7 x ^{3}}{3} + \frac{5}{6} x^{\frac{6}{5}} + C

Solution steps

\int 4 - 7 x^{2} + 5 x d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 4 d x - \int 7 x^{2} d x + \int 5 x d x

\int 4 d x = 4 x

\int 7 x^{2} d x = \frac{7 x ^{3}}{3}

\int 5 x d x = \frac{5}{6} x^{\frac{6}{5}}

= 4 x - \frac{7 x ^{3}}{3} + \frac{5}{6} x^{\frac{6}{5}}

Add a constant to the solution

= 4 x - \frac{7 x ^{3}}{3} + \frac{5}{6} x^{\frac{6}{5}} + C

\int (x z - e^{x} sin (y)) d y

\int 1 + sin (x) \cdot cos (x) d x

\int sinh (u) d u

\int \frac{x ^{4} - 5 x ^{2} + 3 x - 4}{x + 1} d x

\int 3 - y d y

What is the integral of 4-7x^2+\sqrt[5]{x} ?
The integral of 4-7x^2+\sqrt[5]{x} is 4x-(7x^3)/3+5/6 x^{6/5}+C