What is the integral from-infinity to-1 of e^{-30t} ?

The integral from-infinity to-1 of e^{-30t} is diverges

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integral from-infinity to-1 of e^{-30t}

\int_{- \infty}^{- 1} e^{- 30 t} d t

diverges

Solution steps

\int_{- \infty}^{- 1} e^{- 30 t} d t

Compute the indefinite integral:

\int e^{- 30 t} d t = - \frac{1}{30} e^{- 30 t} + C

Compute the boundaries:

\int_{- \infty}^{- 1} e^{- 30 t} d t =

diverges

= diverges

\frac{d}{d x} (\frac{x}{y ^{2} + 1})

\frac{d}{d x} (lo g_{e} (2))

\frac{d ^{2}}{d x ^{2}} (x e^{- \frac{x ^{2}}{2}})

\int x x - 8 d x

3 x^{2} + x y + 3 y^{2} = 7, (1, 1)

What is the integral from-infinity to-1 of e^{-30t} ?
The integral from-infinity to-1 of e^{-30t} is diverges