What is the integral of (22x^3-44x^2+6)/(x^2-2x) ?

The integral of (22x^3-44x^2+6)/(x^2-2x) is 11x^2-6(1/2 ln|x|-1/2 ln|x-2|)+C

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integral of (22x^3-44x^2+6)/(x^2-2x)

\int \frac{22 x ^{3} - 44 x ^{2} + 6}{x ^{2} - 2 x} d x

11 x^{2} - 6 (\frac{1}{2} ln ∣ x ∣ - \frac{1}{2} ln ∣ x - 2 ∣) + C

Solution steps

\int \frac{22 x ^{3} - 44 x ^{2} + 6}{x ^{2} - 2 x} d x

Long division

\frac{22 x ^{3} - 44 x ^{2} + 6}{x ^{2} - 2 x} : 22 x + \frac{6}{x ^{2} - 2 x}

= \int 22 x + \frac{6}{x ^{2} - 2 x} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 22 x d x + \int \frac{6}{x ^{2} - 2 x} d x

\int 22 x d x = 11 x^{2}

\int \frac{6}{x ^{2} - 2 x} d x = - 6 (\frac{1}{2} ln ∣ x ∣ - \frac{1}{2} ln ∣ x - 2 ∣)

= 11 x^{2} - 6 (\frac{1}{2} ln ∣ x ∣ - \frac{1}{2} ln ∣ x - 2 ∣)

Add a constant to the solution

= 11 x^{2} - 6 (\frac{1}{2} ln ∣ x ∣ - \frac{1}{2} ln ∣ x - 2 ∣) + C

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What is the integral of (22x^3-44x^2+6)/(x^2-2x) ?
The integral of (22x^3-44x^2+6)/(x^2-2x) is 11x^2-6(1/2 ln|x|-1/2 ln|x-2|)+C