What is the integral of [arctan(x)] ?

The integral of [arctan(x)] is xarctan(x)-1/2 ln|x^2+1|+C

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integral of [arctan(x)]

\int [arctan (x)] d x

x arctan (x) - \frac{1}{2} ln x^{2} + 1 + C

Solution steps

\int arctan (x) d x

Apply Integration By Parts

: x arctan (x) - \int \frac{x}{x ^{2} + 1} d x

= x arctan (x) - \int \frac{x}{x ^{2} + 1} d x

\int \frac{x}{x ^{2} + 1} d x = \frac{1}{2} ln x^{2} + 1

= x arctan (x) - \frac{1}{2} ln x^{2} + 1

Add a constant to the solution

= x arctan (x) - \frac{1}{2} ln x^{2} + 1 + C

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What is the integral of [arctan(x)] ?
The integral of [arctan(x)] is xarctan(x)-1/2 ln|x^2+1|+C