What is the integral of e^{4x}sin(7x) ?

The integral of e^{4x}sin(7x) is -(7e^{4x}cos(7x))/(65)+(4e^{4x}sin(7x))/(65)+C

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integral of e^{4x}sin(7x)

\int e^{4 x} sin (7 x) d x

- \frac{7 e ^{4 x} cos ( 7 x )}{65} + \frac{4 e ^{4 x} sin ( 7 x )}{65} + C

Solution steps

\int e^{4 x} sin (7 x) d x

Apply Integration By Parts

: - \frac{1}{7} e^{4 x} cos (7 x) - \int - \frac{4}{7} e^{4 x} cos (7 x) d x

= - \frac{1}{7} e^{4 x} cos (7 x) - \int - \frac{4}{7} e^{4 x} cos (7 x) d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - \frac{1}{7} e^{4 x} cos (7 x) - (- \frac{4}{7} \cdot \int e^{4 x} cos (7 x) d x)

Apply Integration By Parts

: \frac{1}{7} e^{4 x} sin (7 x) - \int \frac{4}{7} e^{4 x} sin (7 x) d x

= - \frac{1}{7} e^{4 x} cos (7 x) - (- \frac{4}{7} (\frac{1}{7} e^{4 x} sin (7 x) - \int \frac{4}{7} e^{4 x} sin (7 x) d x))

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - \frac{1}{7} e^{4 x} cos (7 x) - (- \frac{4}{7} (\frac{1}{7} e^{4 x} sin (7 x) - \frac{4}{7} \cdot \int e^{4 x} sin (7 x) d x))

Therefore

\int e^{4 x} sin (7 x) d x = - \frac{1}{7} e^{4 x} cos (7 x) - (- \frac{4}{7} (\frac{1}{7} e^{4 x} sin (7 x) - \frac{4}{7} \cdot \int e^{4 x} sin (7 x) d x))

Isolate

\int e^{4 x} sin (7 x) d x

= - \frac{7 e ^{4 x} cos ( 7 x )}{65} + \frac{4 e ^{4 x} sin ( 7 x )}{65}

Add a constant to the solution

= - \frac{7 e ^{4 x} cos ( 7 x )}{65} + \frac{4 e ^{4 x} sin ( 7 x )}{65} + C

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What is the integral of e^{4x}sin(7x) ?
The integral of e^{4x}sin(7x) is -(7e^{4x}cos(7x))/(65)+(4e^{4x}sin(7x))/(65)+C