What is the integral of 1/(x^{-9)} ?

The integral of 1/(x^{-9)} is (x^{10})/(10)+C

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integral of 1/(x^{-9)}

\int \frac{1}{x ^{- 9}} d x

\frac{x ^{10}}{10} + C

Solution steps

\int \frac{1}{x ^{- 9}} d x

Apply the Power Rule

: \frac{x ^{10}}{10}

= \frac{x ^{10}}{10}

Add a constant to the solution

= \frac{x ^{10}}{10} + C

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What is the integral of 1/(x^{-9)} ?
The integral of 1/(x^{-9)} is (x^{10})/(10)+C