What is the integral of (3x^2-6x+8) ?

The integral of (3x^2-6x+8) is x^3-3x^2+8x+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of (3x^2-6x+8)

\int (3 x^{2} - 6 x + 8) d x

x^{3} - 3 x^{2} + 8 x + C

Solution steps

\int 3 x^{2} - 6 x + 8 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 3 x^{2} d x - \int 6 x d x + \int 8 d x

\int 3 x^{2} d x = x^{3}

\int 6 x d x = 3 x^{2}

\int 8 d x = 8 x

= x^{3} - 3 x^{2} + 8 x

Add a constant to the solution

= x^{3} - 3 x^{2} + 8 x + C

\int \frac{1}{x ^{2} sin ( \frac{π}{x} )} d x

\int \frac{1}{x ^{3} + 2 x ^{2} - 3 x} d x

\int \frac{5}{x ( x + 4 ) ^{2}} d x

\int \frac{x ^{3} - 2}{x ^{2} - x + 3} d x

\int 3 x cos (nπ x) d x

What is the integral of (3x^2-6x+8) ?
The integral of (3x^2-6x+8) is x^3-3x^2+8x+C