What is the integral of-ln(x-2) ?

The integral of-ln(x-2) is -xln(x-2)+2ln(x-2)+x-2+C

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integral of-ln(x-2)

\int - ln (x - 2) d x

- x ln (x - 2) + 2 ln (x - 2) + x - 2 + C

Solution steps

\int - ln (x - 2) d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - \int ln (x - 2) d x

Apply u-substitution

: \int ln (u) d u

= - \int ln (u) d u

Apply Integration By Parts

: u ln (u) - \int 1 d u

= - (u ln (u) - \int 1 d u)

\int 1 d u = u

= - (u ln (u) - u)

Substitute back

u = x - 2

= - ((x - 2) ln (x - 2) - (x - 2))

Simplify

- ((x - 2) ln (x - 2) - (x - 2)) : - x ln (x - 2) + 2 ln (x - 2) + x - 2

= - x ln (x - 2) + 2 ln (x - 2) + x - 2

Add a constant to the solution

= - x ln (x - 2) + 2 ln (x - 2) + x - 2 + C

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What is the integral of-ln(x-2) ?
The integral of-ln(x-2) is -xln(x-2)+2ln(x-2)+x-2+C