What is the solution for (x^2+1)(dy)/(dx)+7x(y-1)=0,y(0)=9 ?

The solution for (x^2+1)(dy)/(dx)+7x(y-1)=0,y(0)=9 is y= 8/((x^2+1)^{7/2)}+1

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(x^2+1)(dy)/(dx)+7x(y-1)=0,y(0)=9

(x^{2} + 1) \frac{d y}{d x} + 7 x (y - 1) = 0, y (0) = 9

y = \frac{8}{( x ^{2} + 1 ) ^{\frac{7}{2}}} + 1

Solution steps

(x^{2} + 1) \frac{d y}{d x} + 7 x (y - 1) = 0

Solve separable ODE:

y = \frac{8}{( x ^{2} + 1 ) ^{\frac{7}{2}}} + 1

y = \frac{8}{( x ^{2} + 1 ) ^{\frac{7}{2}}} + 1

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2 y^{^{'}} + t y = 2

\int_{4}^{9} \frac{1}{x} d x

x \to 5 lim (\frac{x - 5}{∣ x - 5 ∣})

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What is the solution for (x^2+1)(dy)/(dx)+7x(y-1)=0,y(0)=9 ?
The solution for (x^2+1)(dy)/(dx)+7x(y-1)=0,y(0)=9 is y= 8/((x^2+1)^{7/2)}+1