What is the integral of re^{-r} ?

The integral of re^{-r} is -e^{-r}r-e^{-r}+C

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integral of re^{-r}

\int r e^{- r} d r

- e^{- r} r - e^{- r} + C

Solution steps

\int r e^{- r} d r

Apply Integration By Parts

: - e^{- r} r - \int - e^{- r} d r

= - e^{- r} r - \int - e^{- r} d r

\int - e^{- r} d r = e^{- r}

= - e^{- r} r - e^{- r}

Add a constant to the solution

= - e^{- r} r - e^{- r} + C

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