What is the integral of 2t-0.25t^2 ?

The integral of 2t-0.25t^2 is t^2-0.08333…t^3+C

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integral of 2t-0.25t^2

\int 2 t - 0.25 t^{2} d t

t^{2} - 0.08333 \dots t^{3} + C

Solution steps

\int 2 t - 0.25 t^{2} d t

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 2 t d t - \int 0.25 t^{2} d t

\int 2 t d t = t^{2}

\int 0.25 t^{2} d t = 0.08333 \dots t^{3}

= t^{2} - 0.08333 \dots t^{3}

Add a constant to the solution

= t^{2} - 0.08333 \dots t^{3} + C

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What is the integral of 2t-0.25t^2 ?
The integral of 2t-0.25t^2 is t^2-0.08333…t^3+C