What is the integral of e^{1/5 ln(x)} ?

The integral of e^{1/5 ln(x)} is 5/6 x^{6/5}+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of e^{1/5 ln(x)}

\int e^{\frac{1}{5} l n (x)} d x

\frac{5}{6} x^{\frac{6}{5}} + C

Solution steps

\int e^{\frac{1}{5} l n (x)} d x

Simplify

e^{\frac{1}{5} l n (x)} : 5 x

= \int 5 x d x

Apply the Power Rule

: \frac{5}{6} x^{\frac{6}{5}}

= \frac{5}{6} x^{\frac{6}{5}}

Add a constant to the solution

= \frac{5}{6} x^{\frac{6}{5}} + C

\int \frac{12}{( x - 4 ) ( x + 8 )} d x

\int \frac{cos ( x ^{- 1} )}{x ^{2}} d x

\int \frac{x ^{2} + 2}{3} d x

\int \frac{x ^{3} - 1}{( x ^{4} - 4 x ) ^{3}} d x

\int x^{2} sin (y x) d x

What is the integral of e^{1/5 ln(x)} ?
The integral of e^{1/5 ln(x)} is 5/6 x^{6/5}+C