What is the integral of (x^2-1)/(x^3-5x^2+x-5) ?

The integral of (x^2-1)/(x^3-5x^2+x-5) is 12/13 ln|x-5|+1/13 (1/2 ln|x^2+1|+5arctan(x))+C

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integral of (x^2-1)/(x^3-5x^2+x-5)

\int \frac{x ^{2} - 1}{x ^{3} - 5 x ^{2} + x - 5} d x

\frac{12}{13} ln ∣ x - 5 ∣ + \frac{1}{13} (\frac{1}{2} ln x^{2} + 1 + 5 arctan (x)) + C

Solution steps

\int \frac{x ^{2} - 1}{x ^{3} - 5 x ^{2} + x - 5} d x

Take the partial fraction of

\frac{x ^{2} - 1}{x ^{3} - 5 x ^{2} + x - 5} : \frac{12}{13 ( x - 5 )} + \frac{x + 5}{13 ( x ^{2} + 1 )}

= \int \frac{12}{13 ( x - 5 )} + \frac{x + 5}{13 ( x ^{2} + 1 )} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int \frac{12}{13 ( x - 5 )} d x + \int \frac{x + 5}{13 ( x ^{2} + 1 )} d x

\int \frac{12}{13 ( x - 5 )} d x = \frac{12}{13} ln ∣ x - 5 ∣

\int \frac{x + 5}{13 ( x ^{2} + 1 )} d x = \frac{1}{13} (\frac{1}{2} ln x^{2} + 1 + 5 arctan (x))

= \frac{12}{13} ln ∣ x - 5 ∣ + \frac{1}{13} (\frac{1}{2} ln x^{2} + 1 + 5 arctan (x))

Add a constant to the solution

= \frac{12}{13} ln ∣ x - 5 ∣ + \frac{1}{13} (\frac{1}{2} ln x^{2} + 1 + 5 arctan (x)) + C

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What is the integral of (x^2-1)/(x^3-5x^2+x-5) ?
The integral of (x^2-1)/(x^3-5x^2+x-5) is 12/13 ln|x-5|+1/13 (1/2 ln|x^2+1|+5arctan(x))+C