What is the integral of sin(-1x) ?

The integral of sin(-1x) is cos(x)+C

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integral of sin(-1x)

\int sin (- 1 x) d x

cos (x) + C

Solution steps

\int sin (- 1 \cdot x) d x

Simplify

sin (- 1 \cdot x) : - sin (x)

= \int - sin (x) d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - \int sin (x) d x

Use the common integral:

\int sin (x) d x = - cos (x)

= - (- cos (x))

Simplify

= cos (x)

Add a constant to the solution

= cos (x) + C

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