What is the integral of sin(m)xcos(m)x ?

The integral of sin(m)xcos(m)x is 1/3 x^3cos(m)sin(m)+C

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integral of sin(m)xcos(m)x

\int sin (m) x cos (m) x d x

\frac{1}{3} x^{3} cos (m) sin (m) + C

Solution steps

\int sin (m) x cos (m) x d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= cos (m) sin (m) \cdot \int xx d x

Simplify

xx : x^{2}

= cos (m) sin (m) \cdot \int x^{2} d x

Apply the Power Rule

: \frac{x ^{3}}{3}

= cos (m) sin (m) \frac{x ^{3}}{3}

Simplify

cos (m) sin (m) \frac{x ^{3}}{3} : \frac{1}{3} x^{3} cos (m) sin (m)

= \frac{1}{3} x^{3} cos (m) sin (m)

Add a constant to the solution

= \frac{1}{3} x^{3} cos (m) sin (m) + C

\int \frac{1}{2 - x - x ^{2}} d x

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\int \frac{x ^{3} + x ^{- 2}}{x ^{4} - 4 x ^{- 1}} d x

What is the integral of sin(m)xcos(m)x ?
The integral of sin(m)xcos(m)x is 1/3 x^3cos(m)sin(m)+C