What is the integral of (100+t)^4 ?

The integral of (100+t)^4 is ((100+t)^5)/5+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of (100+t)^4

\int (100 + t)^{4} d t

\frac{( 100 + t ) ^{5}}{5} + C

Solution steps

\int (100 + t)^{4} d t

Apply u-substitution

: \int u^{4} d u

= \int u^{4} d u

Apply the Power Rule

: \frac{u ^{5}}{5}

= \frac{u ^{5}}{5}

Substitute back

u = 100 + t

= \frac{( 100 + t ) ^{5}}{5}

Add a constant to the solution

= \frac{( 100 + t ) ^{5}}{5} + C

\int (x^{2} + 5)^{3} 2 x d x

\int - \frac{t ^{2}}{t ^{2} + 4 t + 3} d t

\int \frac{3 x + 1}{x ^{2} + 2 x + 2} d x

\int \frac{2 x ^{3}}{4 + x ^{8}} d x

\int \frac{x ^{4} - 8 x ^{2} + 5 x}{x ^{2}} d x

What is the integral of (100+t)^4 ?
The integral of (100+t)^4 is ((100+t)^5)/5+C