What is the solution for (dy)/(dx)=x^2+x^2y^2,y(0)=1 ?

The solution for (dy)/(dx)=x^2+x^2y^2,y(0)=1 is y=tan((x^3)/3+pi/4)

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(dy)/(dx)=x^2+x^2y^2,y(0)=1

\frac{d y}{d x} = x^{2} + x^{2} y^{2}, y (0) = 1

y = tan (\frac{x ^{3}}{3} + \frac{π}{4})

Solution steps

\frac{d y}{d x} = x^{2} + x^{2} y^{2}

Solve separable ODE:

y = tan (\frac{x ^{3}}{3} + \frac{π}{4})

y = tan (\frac{x ^{3}}{3} + \frac{π}{4})

\frac{\partial}{\partial x} (\frac{0}{0})

\frac{d}{d x} (2 x sin (x) + x^{2} cos (x))

\frac{\partial}{\partial x} (x y^{7} + x^{4} + y^{8})

(- 5, 2), (3, - 7)

\int \frac{3 x + 2}{x ^{2} + 1} d x

What is the solution for (dy)/(dx)=x^2+x^2y^2,y(0)=1 ?
The solution for (dy)/(dx)=x^2+x^2y^2,y(0)=1 is y=tan((x^3)/3+pi/4)