What is the integral of 3sin(4t) ?

The integral of 3sin(4t) is -3/4 cos(4t)+C

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integral of 3sin(4t)

\int 3 sin (4 t) d t

- \frac{3}{4} cos (4 t) + C

Solution steps

\int 3 sin (4 t) d t

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 3 \cdot \int sin (4 t) d t

Apply u-substitution

: \int sin (u) \frac{1}{4} d u

= 3 \cdot \int sin (u) \frac{1}{4} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 3 \cdot \frac{1}{4} \cdot \int sin (u) d u

Use the common integral:

\int sin (u) d u = - cos (u)

= 3 \cdot \frac{1}{4} (- cos (u))

Substitute back

u = 4 t

= 3 \cdot \frac{1}{4} (- cos (4 t))

Simplify

3 \cdot \frac{1}{4} (- cos (4 t)) : - \frac{3}{4} cos (4 t)

= - \frac{3}{4} cos (4 t)

Add a constant to the solution

= - \frac{3}{4} cos (4 t) + C

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