What is the integral of (x^2-3x+2)(cos(x)) ?

The integral of (x^2-3x+2)(cos(x)) is x^2sin(x)+2xcos(x)-3xsin(x)-3cos(x)+C

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integral of (x^2-3x+2)(cos(x))

\int (x^{2} - 3 x + 2) (cos (x)) d x

x^{2} sin (x) + 2 x cos (x) - 3 x sin (x) - 3 cos (x) + C

Solution steps

\int (x^{2} - 3 x + 2) cos (x) d x

Expand

(x^{2} - 3 x + 2) cos (x) : x^{2} cos (x) - 3 x cos (x) + 2 cos (x)

= \int x^{2} cos (x) - 3 x cos (x) + 2 cos (x) d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int x^{2} cos (x) d x - \int 3 x cos (x) d x + \int 2 cos (x) d x

\int x^{2} cos (x) d x = x^{2} sin (x) - 2 (- x cos (x) + sin (x))

\int 3 x cos (x) d x = 3 (x sin (x) + cos (x))

\int 2 cos (x) d x = 2 sin (x)

= x^{2} sin (x) - 2 (- x cos (x) + sin (x)) - 3 (x sin (x) + cos (x)) + 2 sin (x)

Simplify

x^{2} sin (x) - 2 (- x cos (x) + sin (x)) - 3 (x sin (x) + cos (x)) + 2 sin (x) : x^{2} sin (x) + 2 x cos (x) - 3 x sin (x) - 3 cos (x)

= x^{2} sin (x) + 2 x cos (x) - 3 x sin (x) - 3 cos (x)

Add a constant to the solution

= x^{2} sin (x) + 2 x cos (x) - 3 x sin (x) - 3 cos (x) + C

\int 2 x - 4 d x

\int \frac{4 sin ( 3 y - 6 )}{cos ( 3 y )} d y

\int (1 - 2 x) (3 + x) d x

sec^{2} (t)

\int \frac{cos ( ln ( x + 1 ) )}{x + 1} d x

What is the integral of (x^2-3x+2)(cos(x)) ?
The integral of (x^2-3x+2)(cos(x)) is x^2sin(x)+2xcos(x)-3xsin(x)-3cos(x)+C