What is the integral of 1/4 e^{x/4} ?

The integral of 1/4 e^{x/4} is e^{x/4}+C

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integral of 1/4 e^{x/4}

\int \frac{1}{4} e^{\frac{x}{4}} d x

e^{\frac{x}{4}} + C

Solution steps

\int \frac{1}{4} e^{\frac{x}{4}} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{4} \cdot \int e^{\frac{x}{4}} d x

Apply u-substitution

: \int e^{u} \cdot 4 d u

= \frac{1}{4} \cdot \int e^{u} \cdot 4 d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{4} \cdot 4 \cdot \int e^{u} d u

Use the common integral:

\int e^{u} d u = e^{u}

= \frac{1}{4} \cdot 4 e^{u}

Substitute back

u = \frac{x}{4}

= \frac{1}{4} \cdot 4 e^{\frac{x}{4}}

Simplify

\frac{1}{4} \cdot 4 e^{\frac{x}{4}} : e^{\frac{x}{4}}

= e^{\frac{x}{4}}

Add a constant to the solution

= e^{\frac{x}{4}} + C

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