What is the integral of 2/(sqrt(x)(3+\sqrt{x))^2} ?

The integral of 2/(sqrt(x)(3+\sqrt{x))^2} is -4/(3+sqrt(x))+C

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integral of 2/(sqrt(x)(3+\sqrt{x))^2}

\int \frac{2}{x ( 3 + x ) ^{2}} d x

- \frac{4}{3 + x} + C

Solution steps

\int \frac{2}{x ( 3 + x ) ^{2}} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 2 \cdot \int \frac{1}{x ( 3 + x ) ^{2}} d x

Apply u-substitution

: \int \frac{2}{u ^{2}} d u

= 2 \cdot \int \frac{2}{u ^{2}} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 2 \cdot 2 \cdot \int \frac{1}{u ^{2}} d u

Apply the Power Rule

: - \frac{1}{u}

= 2 \cdot 2 (- \frac{1}{u})

Substitute back

u = 3 + x

= 2 \cdot 2 (- \frac{1}{3 + x})

Simplify

2 \cdot 2 (- \frac{1}{3 + x}) : - \frac{4}{3 + x}

= - \frac{4}{3 + x}

Add a constant to the solution

= - \frac{4}{3 + x} + C

\int \frac{1}{49 - 4 x ^{2}} d x

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\int + cos (x) cos (7 x) d x

What is the integral of 2/(sqrt(x)(3+\sqrt{x))^2} ?
The integral of 2/(sqrt(x)(3+\sqrt{x))^2} is -4/(3+sqrt(x))+C