What is the integral of e^{-1/2 ln(x)} ?

The integral of e^{-1/2 ln(x)} is 2sqrt(x)+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of e^{-1/2 ln(x)}

\int e^{- \frac{1}{2} l n (x)} d x

2 x + C

Solution steps

\int e^{- \frac{1}{2} l n (x)} d x

Simplify

e^{- \frac{1}{2} l n (x)} : \frac{1}{x}

= \int \frac{1}{x} d x

Apply the Power Rule

: 2 x^{\frac{1}{2}}

= 2 x^{\frac{1}{2}}

Apply radical rule:

= 2 x

Add a constant to the solution

= 2 x + C

\int \frac{x ^{2} + 1}{( x ^{2} + 1 ) ^{2}} d x

\int \frac{21 x ^{2} - 10 x}{7 x ^{3} - 5 x ^{2} + 13} d x

\int e^{l n (\frac{2 x ^{2} + 2 x + 1}{x + 1})} d x

\int \frac{1}{x ( 200 - x )} d x

\int (\frac{1 - 2 x}{3})^{3} d x

What is the integral of e^{-1/2 ln(x)} ?
The integral of e^{-1/2 ln(x)} is 2sqrt(x)+C