What is the integral of (3x^2-x+1/(2x^3)) ?

The integral of (3x^2-x+1/(2x^3)) is x^3-(x^2)/2-1/(4x^2)+C

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integral of (3x^2-x+1/(2x^3))

\int (3 x^{2} - x + \frac{1}{2 x ^{3}}) d x

x^{3} - \frac{x ^{2}}{2} - \frac{1}{4 x ^{2}} + C

Solution steps

\int 3 x^{2} - x + \frac{1}{2 x ^{3}} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 3 x^{2} d x - \int x d x + \int \frac{1}{2 x ^{3}} d x

\int 3 x^{2} d x = x^{3}

\int x d x = \frac{x ^{2}}{2}

\int \frac{1}{2 x ^{3}} d x = - \frac{1}{4 x ^{2}}

= x^{3} - \frac{x ^{2}}{2} - \frac{1}{4 x ^{2}}

Add a constant to the solution

= x^{3} - \frac{x ^{2}}{2} - \frac{1}{4 x ^{2}} + C

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What is the integral of (3x^2-x+1/(2x^3)) ?
The integral of (3x^2-x+1/(2x^3)) is x^3-(x^2)/2-1/(4x^2)+C