What is the first derivative of (x^2/x) ?

The first derivative of (x^2/x) is 1

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derivative of (x^2/x)

\frac{d}{d x} (\frac{x ^{2}}{x})

1

Solution steps

\frac{d}{d x} (\frac{x ^{2}}{x})

Simplify

\frac{x ^{2}}{x} : x

= \frac{d x}{d x}

Apply the common derivative:

\frac{d x}{d x} = 1

= 1

\int 7 x^{3} (1 + x) d x

x \to 1.9 lim (- x^{2} + 5 x - 2)

x \to - 5 lim (\frac{- 6 x}{x + 5})

\frac{d y}{d t} = - 3 (y - 2)

\frac{\partial}{\partial x} (3 x + 2 x y^{2})