What is the integral of (x^2)/(sqrt(2x-x)) ?

The integral of (x^2)/(sqrt(2x-x)) is 2/5 x^{5/2}+C

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integral of (x^2)/(sqrt(2x-x))

\int \frac{x ^{2}}{2 x - x} d x

\frac{2}{5} x^{\frac{5}{2}} + C

Solution steps

\int \frac{x ^{2}}{2 x - x} d x

Simplify

\frac{x ^{2}}{2 x - x} : x^{\frac{3}{2}}

= \int x^{\frac{3}{2}} d x

Apply the Power Rule

: \frac{2}{5} x^{\frac{5}{2}}

= \frac{2}{5} x^{\frac{5}{2}}

Add a constant to the solution

= \frac{2}{5} x^{\frac{5}{2}} + C

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What is the integral of (x^2)/(sqrt(2x-x)) ?
The integral of (x^2)/(sqrt(2x-x)) is 2/5 x^{5/2}+C