What is the integral of 1/(x^{2/3)} ?

The integral of 1/(x^{2/3)} is 3x^{1/3}+C

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integral of 1/(x^{2/3)}

\int \frac{1}{x ^{\frac{2}{3}}} d x

3 x^{\frac{1}{3}} + C

Solution steps

\int \frac{1}{x ^{\frac{2}{3}}} d x

Apply the Power Rule

: 3 x^{\frac{1}{3}}

= 3 x^{\frac{1}{3}}

Add a constant to the solution

= 3 x^{\frac{1}{3}} + C

\int \frac{x ^{3}}{( x - 2 ) ( x + 3 )} d x

y = \frac{x ^{2}}{x + 3}, (2, \frac{4}{5})

f (x) = 4 x^{2} + 1

y^{^{'}} + \frac{1}{2} y = 8, y (0) = 2

\frac{\partial}{\partial x} (\frac{( x v ^{2} )}{( x ^{2} + v ^{2} )})