What is the integral of (12x^3+6x-2) ?

The integral of (12x^3+6x-2) is 3x^4+3x^2-2x+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of (12x^3+6x-2)

\int (12 x^{3} + 6 x - 2) d x

3 x^{4} + 3 x^{2} - 2 x + C

Solution steps

\int 12 x^{3} + 6 x - 2 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 12 x^{3} d x + \int 6 x d x - \int 2 d x

\int 12 x^{3} d x = 3 x^{4}

\int 6 x d x = 3 x^{2}

\int 2 d x = 2 x

= 3 x^{4} + 3 x^{2} - 2 x

Add a constant to the solution

= 3 x^{4} + 3 x^{2} - 2 x + C

\int \frac{3}{4 x ^{2}} d x

\int \frac{e ^{8 x}}{e ^{8 x} + 3} d x

\int x^{2} + 2 x + 5 d x

\int \frac{1}{( a ^{2} + z ^{2} ) ^{\frac{3}{2}}} d z

\int \frac{5 x}{( 2 x + 1 ) ( x - 7 )} d x

What is the integral of (12x^3+6x-2) ?
The integral of (12x^3+6x-2) is 3x^4+3x^2-2x+C