What is the integral of (ln(q))/(q^2) ?

The integral of (ln(q))/(q^2) is -(ln(q))/q-1/q+C

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integral of (ln(q))/(q^2)

\int \frac{ln ( q )}{q ^{2}} d q

- \frac{ln ( q )}{q} - \frac{1}{q} + C

Solution steps

\int \frac{ln ( q )}{q ^{2}} d q

Apply Integration By Parts

: - \frac{ln ( q )}{q} - \int - \frac{1}{q ^{2}} d q

= - \frac{ln ( q )}{q} - \int - \frac{1}{q ^{2}} d q

\int - \frac{1}{q ^{2}} d q = \frac{1}{q}

= - \frac{ln ( q )}{q} - \frac{1}{q}

Add a constant to the solution

= - \frac{ln ( q )}{q} - \frac{1}{q} + C

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What is the integral of (ln(q))/(q^2) ?
The integral of (ln(q))/(q^2) is -(ln(q))/q-1/q+C