What is the integral of x^2(2y)/1 ^2 ?

The integral of x^2(2y)/1 ^2 is d^2y(x^4)/2+C

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integral of x^2(2y)/1 ^2

\int x^{2} \frac{d ^{2} y}{1} d x^{2}

d^{2} y \frac{x ^{4}}{2} + C

Solution steps

\int x^{2} \frac{d ^{2} y}{1} d x^{2}

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= d^{2} y \cdot \int x^{2} d x^{2}

Apply the Power Rule

: \frac{x ^{4}}{2}

= d^{2} y \frac{x ^{4}}{2}

Add a constant to the solution

= d^{2} y \frac{x ^{4}}{2} + C

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What is the integral of x^2(2y)/1 ^2 ?
The integral of x^2(2y)/1 ^2 is d^2y(x^4)/2+C