What is the integral of 3x^2-4x+12 ?

The integral of 3x^2-4x+12 is x^3-2x^2+12x+C

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integral of 3x^2-4x+12

\int 3 x^{2} - 4 x + 12 d x

x^{3} - 2 x^{2} + 12 x + C

Solution steps

\int 3 x^{2} - 4 x + 12 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 3 x^{2} d x - \int 4 x d x + \int 12 d x

\int 3 x^{2} d x = x^{3}

\int 4 x d x = 2 x^{2}

\int 12 d x = 12 x

= x^{3} - 2 x^{2} + 12 x

Add a constant to the solution

= x^{3} - 2 x^{2} + 12 x + C

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What is the integral of 3x^2-4x+12 ?
The integral of 3x^2-4x+12 is x^3-2x^2+12x+C