What is the integral of-(ln(x))/2 ?

The integral of-(ln(x))/2 is -1/2 (xln(x)-x)+C

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integral of-(ln(x))/2

\int - \frac{ln ( x )}{2} d x

- \frac{1}{2} (x ln (x) - x) + C

Solution steps

\int - \frac{ln ( x )}{2} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - \frac{1}{2} \cdot \int ln (x) d x

Apply Integration By Parts

: x ln (x) - \int 1 d x

= - \frac{1}{2} (x ln (x) - \int 1 d x)

\int 1 d x = x

= - \frac{1}{2} (x ln (x) - x)

Add a constant to the solution

= - \frac{1}{2} (x ln (x) - x) + C

u^{'} (t)

\frac{\partial}{\partial y} (arctan (x - y))

x \to \infty + lim (0)

\int sec^{2} (2 x + 1) d x

\frac{\partial}{\partial x} (2 x - 5)

What is the integral of-(ln(x))/2 ?
The integral of-(ln(x))/2 is -1/2 (xln(x)-x)+C