What is the integral of 0.9x^2-0.04x^3 ?

The integral of 0.9x^2-0.04x^3 is 0.3x^3-0.01x^4+C

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integral of 0.9x^2-0.04x^3

\int 0.9 x^{2} - 0.04 x^{3} d x

0.3 x^{3} - 0.01 x^{4} + C

Solution steps

\int 0.9 x^{2} - 0.04 x^{3} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 0.9 x^{2} d x - \int 0.04 x^{3} d x

\int 0.9 x^{2} d x = 0.3 x^{3}

\int 0.04 x^{3} d x = 0.01 x^{4}

= 0.3 x^{3} - 0.01 x^{4}

Add a constant to the solution

= 0.3 x^{3} - 0.01 x^{4} + C

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What is the integral of 0.9x^2-0.04x^3 ?
The integral of 0.9x^2-0.04x^3 is 0.3x^3-0.01x^4+C