What is the integral of (e^x-6x)^2 ?

The integral of (e^x-6x)^2 is 1/2 e^{2x}-12(e^xx-e^x)+12x^3+C

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integral of (e^x-6x)^2

\int (e^{x} - 6 x)^{2} d x

\frac{1}{2} e^{2 x} - 12 (e^{x} x - e^{x}) + 12 x^{3} + C

Solution steps

\int (e^{x} - 6 x)^{2} d x

Expand

(e^{x} - 6 x)^{2} : e^{2 x} - 12 e^{x} x + 36 x^{2}

= \int e^{2 x} - 12 e^{x} x + 36 x^{2} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int e^{2 x} d x - \int 12 e^{x} x d x + \int 36 x^{2} d x

\int e^{2 x} d x = \frac{1}{2} e^{2 x}

\int 12 e^{x} x d x = 12 (e^{x} x - e^{x})

\int 36 x^{2} d x = 12 x^{3}

= \frac{1}{2} e^{2 x} - 12 (e^{x} x - e^{x}) + 12 x^{3}

Add a constant to the solution

= \frac{1}{2} e^{2 x} - 12 (e^{x} x - e^{x}) + 12 x^{3} + C

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What is the integral of (e^x-6x)^2 ?
The integral of (e^x-6x)^2 is 1/2 e^{2x}-12(e^xx-e^x)+12x^3+C