What is the integral of 3x^2(e^x)^3 ?

The integral of 3x^2(e^x)^3 is e^{3x}x^2-2/3 e^{3x}x+2/9 e^{3x}+C

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integral of 3x^2(e^x)^3

integral

3 x^{2} (e^{x})^{3}

e^{3 x} x^{2} - \frac{2}{3} e^{3 x} x + \frac{2}{9} e^{3 x} + C

Solution steps

\int 3 x^{2} (e^{x})^{3} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 3 \cdot \int x^{2} (e^{x})^{3} d x

Apply Integration By Parts

: \frac{1}{3} e^{3 x} x^{2} - \int \frac{2}{3} e^{3 x} x d x

= 3 (\frac{1}{3} e^{3 x} x^{2} - \int \frac{2}{3} e^{3 x} x d x)

\int \frac{2}{3} e^{3 x} x d x = \frac{2}{27} (3 e^{3 x} x - e^{3 x})

= 3 (\frac{1}{3} e^{3 x} x^{2} - \frac{2}{27} (3 e^{3 x} x - e^{3 x}))

Simplify

3 (\frac{1}{3} e^{3 x} x^{2} - \frac{2}{27} (3 e^{3 x} x - e^{3 x})) : e^{3 x} x^{2} - \frac{2}{3} e^{3 x} x + \frac{2}{9} e^{3 x}

= e^{3 x} x^{2} - \frac{2}{3} e^{3 x} x + \frac{2}{9} e^{3 x}

Add a constant to the solution

= e^{3 x} x^{2} - \frac{2}{3} e^{3 x} x + \frac{2}{9} e^{3 x} + C

sin (4 x)

\int \frac{1}{( 1 - 9 x ^{2} ) ^{\frac{3}{2}}} d x

\int \frac{1}{3} x^{5} d x

\int + 9 ln (x^{2} - 1) d x

\int \frac{x ^{3} + 4 x + 3}{x ^{2} + 2} d x

What is the integral of 3x^2(e^x)^3 ?
The integral of 3x^2(e^x)^3 is e^{3x}x^2-2/3 e^{3x}x+2/9 e^{3x}+C