What is the integral of x/((2x-1)^3) ?

The integral of x/((2x-1)^3) is -1/(4(2x-1))-1/(8(2x-1)^2)+C

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integral of x/((2x-1)^3)

\int \frac{x}{( 2 x - 1 ) ^{3}} d x

- \frac{1}{4 ( 2 x - 1 )} - \frac{1}{8 ( 2 x - 1 ) ^{2}} + C

Solution steps

\int \frac{x}{( 2 x - 1 ) ^{3}} d x

Take the partial fraction of

\frac{x}{( 2 x - 1 ) ^{3}} : \frac{1}{2 ( 2 x - 1 ) ^{2}} + \frac{1}{2 ( 2 x - 1 ) ^{3}}

= \int \frac{1}{2 ( 2 x - 1 ) ^{2}} + \frac{1}{2 ( 2 x - 1 ) ^{3}} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int \frac{1}{2 ( 2 x - 1 ) ^{2}} d x + \int \frac{1}{2 ( 2 x - 1 ) ^{3}} d x

\int \frac{1}{2 ( 2 x - 1 ) ^{2}} d x = - \frac{1}{4 ( 2 x - 1 )}

\int \frac{1}{2 ( 2 x - 1 ) ^{3}} d x = - \frac{1}{8 ( 2 x - 1 ) ^{2}}

= - \frac{1}{4 ( 2 x - 1 )} - \frac{1}{8 ( 2 x - 1 ) ^{2}}

Add a constant to the solution

= - \frac{1}{4 ( 2 x - 1 )} - \frac{1}{8 ( 2 x - 1 ) ^{2}} + C

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What is the integral of x/((2x-1)^3) ?
The integral of x/((2x-1)^3) is -1/(4(2x-1))-1/(8(2x-1)^2)+C