What is the integral of ((e^{x/2}-e^{-x/2})^2)/4 ?

The integral of ((e^{x/2}-e^{-x/2})^2)/4 is 1/4 (e^xx-2x+e^{-x}x-2xcosh(x)+2sinh(x))+C

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integral of ((e^{x/2}-e^{-x/2})^2)/4

\int \frac{( e ^{\frac{x}{2}} - e ^{- \frac{x}{2}} ) ^{2}}{4} d x

\frac{1}{4} (e^{x} x - 2 x + e^{- x} x - 2 x cosh (x) + 2 sinh (x)) + C

Solution steps

\int \frac{( e ^{\frac{x}{2}} - e ^{- \frac{x}{2}} ) ^{2}}{4} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{4} \cdot \int (e^{\frac{x}{2}} - e^{- \frac{x}{2}})^{2} d x

Apply Integration By Parts

: (e^{\frac{x}{2}} - e^{- \frac{x}{2}})^{2} x - \int (e^{x} - e^{- x}) x d x

= \frac{1}{4} ((e^{\frac{x}{2}} - e^{- \frac{x}{2}})^{2} x - \int (e^{x} - e^{- x}) x d x)

\int (e^{x} - e^{- x}) x d x = 2 x cosh (x) - 2 sinh (x)

= \frac{1}{4} ((e^{\frac{x}{2}} - e^{- \frac{x}{2}})^{2} x - (2 x cosh (x) - 2 sinh (x)))

Expand

(e^{\frac{x}{2}} - e^{- \frac{x}{2}})^{2} x - (2 x cosh (x) - 2 sinh (x)) : e^{x} x - 2 x + e^{- x} x - 2 x cosh (x) + 2 sinh (x)

= \frac{1}{4} (e^{x} x - 2 x + e^{- x} x - 2 x cosh (x) + 2 sinh (x))

Add a constant to the solution

= \frac{1}{4} (e^{x} x - 2 x + e^{- x} x - 2 x cosh (x) + 2 sinh (x)) + C

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What is the integral of ((e^{x/2}-e^{-x/2})^2)/4 ?
The integral of ((e^{x/2}-e^{-x/2})^2)/4 is 1/4 (e^xx-2x+e^{-x}x-2xcosh(x)+2sinh(x))+C