What is the integral of (3x^4-5x^2-4) ?

The integral of (3x^4-5x^2-4) is (3x^5)/5-(5x^3)/3-4x+C

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integral of (3x^4-5x^2-4)

\int (3 x^{4} - 5 x^{2} - 4) d x

\frac{3 x ^{5}}{5} - \frac{5 x ^{3}}{3} - 4 x + C

Solution steps

\int 3 x^{4} - 5 x^{2} - 4 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 3 x^{4} d x - \int 5 x^{2} d x - \int 4 d x

\int 3 x^{4} d x = \frac{3 x ^{5}}{5}

\int 5 x^{2} d x = \frac{5 x ^{3}}{3}

\int 4 d x = 4 x

= \frac{3 x ^{5}}{5} - \frac{5 x ^{3}}{3} - 4 x

Add a constant to the solution

= \frac{3 x ^{5}}{5} - \frac{5 x ^{3}}{3} - 4 x + C

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What is the integral of (3x^4-5x^2-4) ?
The integral of (3x^4-5x^2-4) is (3x^5)/5-(5x^3)/3-4x+C