What is the integral of (4x+\sqrt[3]{x}) ?

The integral of (4x+\sqrt[3]{x}) is 2x^2+3/4 x^{4/3}+C

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integral of (4x+\sqrt[3]{x})

2 x^{2} + \frac{3}{4} x^{\frac{4}{3}} + C

Solution steps

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

\int 4 x d x = 2 x^{2}

= 2 x^{2} + \frac{3}{4} x^{\frac{4}{3}}

Add a constant to the solution

= 2 x^{2} + \frac{3}{4} x^{\frac{4}{3}} + C

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What is the integral of (4x+\sqrt[3]{x}) ?
The integral of (4x+\sqrt[3]{x}) is 2x^2+3/4 x^{4/3}+C