What is the integral of 40000w 5/2+(3w 4/3)/4 ?

The integral of 40000w 5/2+(3w 4/3)/4 is 50000w^2+(w^2)/2+C

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integral of 40000w 5/2+(3w 4/3)/4

\int 40000 w \frac{5}{2} + \frac{3 w \frac{4}{3}}{4} d w

50000 w^{2} + \frac{w ^{2}}{2} + C

Solution steps

\int 40000 w \frac{5}{2} + \frac{3 w \frac{4}{3}}{4} d w

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 40000 w \frac{5}{2} d w + \int \frac{3 w \frac{4}{3}}{4} d w

\int 40000 w \frac{5}{2} d w = 50000 w^{2}

\int \frac{3 w \frac{4}{3}}{4} d w = \frac{w ^{2}}{2}

= 50000 w^{2} + \frac{w ^{2}}{2}

Add a constant to the solution

= 50000 w^{2} + \frac{w ^{2}}{2} + C

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What is the integral of 40000w 5/2+(3w 4/3)/4 ?
The integral of 40000w 5/2+(3w 4/3)/4 is 50000w^2+(w^2)/2+C