What is the integral of (6x^2-5)e^{2x^3-5x} ?

The integral of (6x^2-5)e^{2x^3-5x} is e^{2x^3-5x}+C

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integral of (6x^2-5)e^{2x^3-5x}

\int (6 x^{2} - 5) e^{2 x^{3} - 5 x} d x

e^{2 x^{3} - 5 x} + C

Solution steps

\int (6 x^{2} - 5) e^{2 x^{3} - 5 x} d x

Apply u-substitution

: \int e^{u} d u

= \int e^{u} d u

Use the common integral:

\int e^{u} d u = e^{u}

= e^{u}

Substitute back

u = 2 x^{3} - 5 x

= e^{2 x^{3} - 5 x}

Add a constant to the solution

= e^{2 x^{3} - 5 x} + C

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What is the integral of (6x^2-5)e^{2x^3-5x} ?
The integral of (6x^2-5)e^{2x^3-5x} is e^{2x^3-5x}+C