What is the integral of e^{4x}x^{-1} ?

The integral of e^{4x}x^{-1} is \Ei(4x)+C

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integral of e^{4x}x^{-1}

\int e^{4 x} x^{- 1} d x

Ei (4 x) + C

Solution steps

\int e^{4 x} x^{- 1} d x

Simplify

e^{4 x} x^{- 1} : \frac{e ^{4 x}}{x}

= \int \frac{e ^{4 x}}{x} d x

Apply u-substitution

: \int \frac{e ^{u}}{u} d u

= \int \frac{e ^{u}}{u} d u

Use the nonelementary integral:

\int \frac{e ^{x}}{x} d x = Ei (x)

= Ei (u)

Substitute back

u = 4 x

= Ei (4 x)

Add a constant to the solution

= Ei (4 x) + C

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What is the integral of e^{4x}x^{-1} ?
The integral of e^{4x}x^{-1} is \Ei(4x)+C